Question #299756

Four charges, q1 =5.00 x10-7C,   q2 = -3.00 x10-7 C,   q3 = -2.00 x10-7C,   q4 = 6.00 x10-7C, are situated at the corners of a square of side 4.00m. Find the potential at the center of the square?



1
Expert's answer
2022-02-19T04:55:58-0500

Given:

q1=5.00107C,q2=3.00107Cq_1=5.00*10^{-7}\:{\rm C},\quad q_2=-3.00*10^{-7}\:\rm C

q3=2.00107C,q4=6.00107Cq_3=-2.00*10^{-7}\:{\rm C},\quad q_4=6.00*10^{-7}\:\rm C

r=224.00m=2.83mr=\frac{\sqrt{2}}{2}*4.00\:\rm m=2.83\: m


The net potential at the center of square

V=V1+V2+V3+V4V=V_1+V_2+V_3+V_4

V=kr(q1+q2+q3+q4)V=\frac{k}{r}(q_1+q_2+q_3+q_4)

V=91092.83(5.003.002.00+6.00)107=1910VV=\frac{9*10^9}{2.83}(5.00-3.00-2.00+6.00)*10^{-7}=1910\:\rm V


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