Answer to Question #299756 in Physics for kelly

Question

Four charges, q₁ =5.00 x10^-7C,   q₂ = -3.00 x^10-7 C,   q₃ = -2.00 x10^-7C,   q₄ = 6.00 x10^-7C, are situated at the corners of a square of side 4.00m. Find the potential at the center of the square?

Answer 1

Given:

$q_1=5.00*10^{-7}\:{\rm C},\quad q_2=-3.00*10^{-7}\:\rm C$

$q_3=-2.00*10^{-7}\:{\rm C},\quad q_4=6.00*10^{-7}\:\rm C$

$r=\frac{\sqrt{2}}{2}*4.00\:\rm m=2.83\: m$

The net potential at the center of square

$$V=V_1+V_2+V_3+V_4$$

$$V=\frac{k}{r}(q_1+q_2+q_3+q_4)$$

$$V=\frac{9*10^9}{2.83}(5.00-3.00-2.00+6.00)*10^{-7}=1910\:\rm V$$