Question #299527

A crate weighing 490 N is pushed along a surface. If it takes 126 N to get the crate starts to move (a = 0), what is its static friction and coefficient of static friction μs? Solve the unknown and confirm your answer of static friction using the Phet Simulation software. (Use the part of with Acceleration in Phet Simulation)




1
Expert's answer
2022-02-18T15:53:55-0500

The static friction force by definition

Ff=μsN=μsmgF_f=\mu_sN=\mu_s mg

The static friction force


Ff=F=126NF_f=F=\rm 126\: N

The static friction coefficient

μs=Ffmg=126490=0.257\mu_s=\frac{F_f}{mg}=\frac{126}{490}=0.257


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