Answer to Question #299320 in Physics for yumi

Question

Calculate the magnitude and direction of the electric field at a point P which is 30 cm to the right of a point charge Q = -3.0 x 10-6 C

Answer 1

Given:

$Q = -3.0 *10^{-6}\:\rm C$

$r=0.3\:\rm m$

The magnitude of electric field at the point P

$$E=k\frac{|Q|}{r^2}=9*10^9*\frac{3.0 *10^{-6}}{0.3^2}=3*10^5\:\rm V/m$$

The field is directed toward the charge.