Question #299349

A 0.0450-π‘˜π‘” golf ball initially at rest is given a speed of 25.0 π‘š/𝑠 when a club strikes it. If the club and ball are in contact for 2.00 π‘šπ‘ , what average force acts on the ball? Is the effect of the ball’s weight during the time of contact significant? Why or why not?


1
Expert's answer
2022-02-18T08:21:52-0500

Given:

m=0.0450β€…kgm=0.0450\:\rm kg

Ξ”v=25.0β€…m/s\Delta v=25.0\:\rm m/s

Ξ”t=0.002β€…s\Delta t=0.002\:\rm s


The average force on the ball

F=ma=mΞ”vΞ”t=0.045βˆ—25.0/0.002=562.5β€…NF=ma=m\frac{\Delta v}{\Delta t}\\ =0.045*25.0/0.002=562.5\:\rm N

The effect of the ball’s weight during the time of contact is significant.


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