Answer to Question #296434 in Physics for Kev

Question #296434

A load at rest on the floor is subjected to a force making it move a certain distance. The work produce is 2000 J. The load was acted on by the force for 2 seconds. What is the amount of power?

Expert's answer

Given:

$W=2000\: \rm J$

$t=2\:\rm s$

The amount of power

P=\frac{W}{t}=\rm\frac{2000\:\rm J}{2\:\rm s}=1000\: W=1\:kW

Learn more about our help with Assignments: Physics

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. A force of 500 N acts horizontally on a load at rest on the floor. The load moves a distance of 20 m
2. An airliner must reach a speed of 110m/s to take off. If the available runway is 2.4 km and the airc
3. A point of charge 10×10^-6C has a potential of 4×10^4V from a point 2mm from it. Calculate the pot
4. A body of mass 25kg falls on the ground from a height of 19.6m. The body penetrates into the ground.
5. A copper rod whose length at 30m is 10.0m is heated to 50oc . Find its new length liner expansityfo
6. The wave length of a travelling wave is 5m at a frequency of 12Hz and has an amplitude of 15m, write
7. What is the amount of heat required to change 2kg of ice at -15°c to water at 70°c ( C=4200jkg-¹k