Answer to Question #296434 in Physics for Kev

Question

A load at rest on the floor is subjected to a force making it move a certain distance. The work produce is 2000 J. The load was acted on by the force for 2 seconds. What is the amount of power?

Answer 1

Given:

$W=2000\: \rm J$

$t=2\:\rm s$

The amount of power

$$P=\frac{W}{t}=\rm\frac{2000\:\rm J}{2\:\rm s}=1000\: W=1\:kW$$