Answer to Question #296395 in Physics for Yusuf

Question

The wave length of a travelling wave is 5m at a frequency of 12Hz and has an amplitude of 15m, write down the equation of wave

Answer 1

Given:

$\lambda=5\:\rm m$

$f=12\:\rm Hz$

$A=15\:\rm m$

 The equation of wave is given by

$y(x,t)=A\sin\left(\frac{2\pi}{\lambda}x-2\pi f t\right)$

$y(x,t)=(15\:{\rm m})\sin\left(\frac{2\pi}{5}x-2\pi *12 t\right)$

$y(x,t)=(15\:{\rm m})\sin\left(0.4\pi x-24\pi t\right)$