Question

A copper rod whose length at 30m is 10.0m is heated to 50oc . Find its new length liner expansityfor copper as 0.00017k^-1

Answer 1

Given:

$l_0=10\:\rm m$

$t_1=30^\circ \rm C$

$t_2=50^\circ \rm C$

$\alpha=0.00017\:\rm K^{-1}$

The linear thermal expansion equation says

$$l=l_0(1+\alpha\Delta t)$$

$$l=10(1+0.00017*20)=10.034\:\rm m$$