Answer
the theory and procedure for the experiment to determine Plank’s constant by
Photo electric apparatus is as follows
Step i)if the potential is small then the potential
energy at the anode is less than the kinetic energy of
the electrons and there is a current through the tube.
Step ii) if the potential is large enough the
potential energy at the anode is larger than the kinetic
energy and the electrons are driven back to the
cathode. In this case, there is no current.
Step iii) The third case is if the voltage just stops the
electrons (with maximum kinetic energy Tmax) from
reaching the anode. The voltage required to do this is called the “stopping potential" (V0). A typical I-
V characteristics for a given frequency of light is also as below.
Thus we can be rewritten as,
"eV_0=h\\nu-e\\phi\\\\V_0=h\\nu\/e-\\phi"
It is worth noting here that, since the anode and cathode surfaces are different, an additional
contact potential “A” comes into the picture which simply gets added to the work function
“Φ”. can be written in terms of wavelength as
Standard value of h is known1
to be "6.626\u00d710^{-34}J-s" .
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