L = 25 m
m = 300 g = 0.3 kg
I = 35 A
The force acting on the current carrying wire in uniform magnetic field
F = BILsinθ
F= BIL (θ = 90º)
Weight of the wire w = mg
BIL = mg
"B = \\frac{mg}{IL} \\\\\n\nB = \\frac{0.3 \\times 9.8}{35 \\times 25} = 0.00336 = 3.36 \\times 10^{-3} \\;T"
Answer: "3.36 \\times 10^{-3} \\;T"
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