Prove that the sum of two convergent sequence is convergent.
Let A and B be the points of convergence of the two respective series. The convergence of the two series implies that given any "\\varepsilon>0" , there exists an integer "N_{0}" such that for any "N \\geq N_{0}" , we have
"\\begin{aligned}\n\n&\\left|A-\\sum_{n=1}^{N} a_{n}\\right|<\\varepsilon \\\\\n\n&\\left|B-\\sum_{n=1}^{N} b_{n}\\right|<\\varepsilon\n\n\\end{aligned}"
We claim that "\\sum_{n=1}^{\\infty} \\frac{a_{n}+b_{n}}{2}" converges to "\\frac{A+B}{2}" . Indeed, for all "N \\geq N_{0}" , we can use the triangle inequality to get
"\\left|\\frac{A+B}{2}-\\sum_{n=1}^{N} \\frac{a_{n}+b_{n}}{2}\\right| \\leq \\frac{1}{2}\\left|A-\\sum_{n=1}^{N} a_{n}\\right|+\\frac{1}{2}\\left|B-\\sum_{n=1}^{N} b_{n}\\right|<\\varepsilon"
Hence, the sum of two convergent sequence is convergent.
Comments
Leave a comment