Question #207312

Prove that the following series is convergent for all š‘Ÿ ∈ ā„

Ī£ (1 + 1/2 + ... + 1/n) (sin (nr) / n).



Expert's answer

let:

an=Σ(1/n)n∣sin(nr)∣a_n=\frac{Σ ( 1/n)}{ n}|sin(nr)|


bn=Ī£(1/n)nb_n=\frac{Ī£ ( 1/n)}{ n}


∣sin(nr)āˆ£ā‰¤1|sin (nr)|\le 1 , then:

an≤bna_n\le b_n


also:

bnā‰¤āˆ‘(1/n2)b_n\le \sum (1/n^2)


So, since āˆ‘(1/n2)\sum (1/n^2) converges, bn=Ī£(1/n)nb_n=\frac{Ī£ ( 1/n)}{ n} converges as well

so, āˆ‘bn\sum b_n converges

then, āˆ‘an\sum a_n converges


so, series āˆ‘(1+1/2+...+1/n)sin(nr)n\sum (1+1/2+...+1/n)\frac{sin(nr)}{n} converges


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS