Find the minimum amount of tin sheet in square inches that can be made into a closed cylinder having a volume of 108 cubic inches
"V=\\pi R^2L=108"
"L=108\/\\pi R^2"
"S=2\\pi RL+2\\pi R^2=216\/R+2\\pi R^2"
"\\frac{dS}{dR}=-216\/R^2+4\\pi R=0"
"4\\pi R^3-216=0"
"R^3=216\/(4\\pi)"
"R_{min}=2.58\\ in"
"S_{min}=216\/2.58+2\\pi\\cdot2.58^2=125.53\\ in^2"
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