Question #184539

  1. Use mathematical induction to show that n! ≥ 2(n-1) for all n ≥ 1.
  2. Use (1) and the definition of a Cauchy sequence to show that Sn = ( 1+ 1/2! + 1/3! + ⋯ 1/n!) is Cauchy sequence.

Expert's answer


(i)


n! ≥ 2(n-1)


For P(2) = 2!≥2(2−1)2! \geq 2(2-1)

2=2


for P(3)= 3!≥2(3−1)3! \geq 2(3-1)

6>4


now for

P(k)


The inductive hypothesis is

k!≥2(k−1)\boxed{k! \geq 2(k-1)}



(ii)

by using


n! ≥ 2(n-1)


and using definition of a Cauchy sequence


∣an+p−an∣=1(n+1)!+1(n+2)!+..........+1(n+p)!|a_{n+p}-a_{n}|= \frac{1}{(n+1)!}+\frac{1}{(n+2)!}+..........+\frac{1}{(n+p)!}


≤1n(n+1)+1(n+1)(n+2)+...........+1(n+p−1)(n+2)\leq \frac{1}{n(n+1)}+\frac{1}{(n+1)(n+2)}+...........+\frac{1}{(n+p-1)(n+2)}

=1n−1n+p=\frac{1}{n}-\frac{1}{n+p}


≤1n\leq\frac{1}{n}

hence proved

Sn=(1+12!+13!..................+1n!\boxed{S_n = ( 1+\frac{1}{2!}+\frac{1}{3!}..................+\frac{1}{n!} }



LATEST TUTORIALS
APPROVED BY CLIENTS