Under certain conditions, cane sugar is converted into dextrose at a rate, which is proportional to the amount unconverted at any time. If out of 60 grams of sugar at t = 0 6 grams are converted during the first 4 minutes, find the amount converted in 2 hours.
"\ud835\udc36(\ud835\udc61) = 60 \u22c5 ( 1 \u2212 \ud835\udc52 ^{\u2212\ud835\udc61\u22c5ln|( \\frac{60 }{54}) ^\\frac{1 }{4}|} ) = 60\u22c5 ( 1 \u2212 \ud835\udc52^{ ln|( \\frac{60 }{54}) \u2212\\frac{\ud835\udc61}{ 4}}| )"
"= 60 \u22c5 (1 \u2212 ( \\frac{60}{ 54})^\\frac {\u2212\ud835\udc61}{ 4})"
"C(120)= 60 \u22c5 (1 \u2212 ( \\frac{54}{ 60})^\\frac {120}{ 4})=57.45g"
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