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Rhodobacter lauracita is a newly discovered bacterium and is a manganesebased photoautotrophy. Light provides the energy necessary to drive the production of organic carbon. (Be careful, this question set is asking about assimilation, rather than dissimilation reactions) a. How much free energy in kJ/mol would be required to form one mole of glucose (C6H12O6) if reduced manganese (Mn2+) served as the electron donor for R. lauracita? Assume that Mn2+ is oxidized to the solid MnO2 (activity = 1), pH = 7, and that Mn2+ and glucose are present at 10-4 M. The partial pressure of carbon dioxide is 10-3.5 atm. Give the answer in kJ per mole of glucose produced. E0’ (V) 1/2 MnO2(s) + 2 H+ + e- = 1/2 Mn2+ + H2O +0.58 1/4 CO2(g) + H+ + e- = 1/24 C6H12O6 + 1/4 H2O -0.43 Fe(OH)3(am) + 3 H+ + e- = Fe2+ + 3 H 2O +0.06
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