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Determination of the new concentration of Dye and NaClO A student has the following solutions available to them. - Dye (1.23 x 10-6 mol L-1) – set to dispense in 1 mL aliquots. - Deionised water – set to dispense in 0.5 mL aliquots - NaClO (0.8 mol L-1) dispensed using a graduated pipette. The student is assigned to Run 1. Calculate the initial concentration of dye and bleach in this run. Answer to 2 significant figures. -Run 1 - Dye (3.0mL) -Deionised water (1.0mL) -NaClO (0.50mL) New concentration of Dye (mol L-1) ＝ ___ x 10^-7 New concentration of NaClO (mol L-1) ＝ ___ x 10^-2
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