My orders
How it works
Examples
Reviews
Blog
Homework Answers
Submit
Sign in
How it works
Examples
Reviews
Homework answers
Blog
Contact us
Submit
Fill in the order form to get the price
Subject
Select Subject
Programming & Computer Science
Math
Engineering
Economics
Physics
Other
Category
Mechanics | Relativity
Electricity and Magnetism
Quantum Mechanics
Molecular Physics | Thermodynamics
Solid State Physics
Atomic and Nuclear Physics
Field Theory
Plasma Physics
Other
Deadline
Timezone:
Title
*
Task
*
{"ops":[{"insert":"I have just recently been introduced to the Kalmeyer-Laughling wavefunction\n\n$\u00a0\u00a0\u00a0\\psi(s_1,\\dots,s_N) \\propto \\delta_s \\prod_{i<j} (z_i-z_j)^{\\frac{s_is_j}{2}-\\frac{1}{2}}\\prod_k e^{\\frac{i\\pi}{2}(k-1)(s_k+1)}$\n\nwhere we consider a lattice in two dimensions, and on each lattice site there is a spin-1\/2 particles in either state up or state down, $s_i = \\pm 1$. $\\delta_s$ is 1 if the sum of the spin is zero, zero otherwise. I am bit confused about the $k$, but i believe it is simply a product over every lattice site?\n\nI want to rewrite the wavefunction using occupation numbers instead, so $s_j = 2n_j-1$ where $n_j$ is the number of particles on site $j$. I should be able to get the following form:\n\n$\u00a0\u00a0\\psi(n_1,\\dots,n_N) \\propto \\delta_n \\prod_{i<j}(z_i-z_j)^{2n_in_j}\\prod_{i\\neq j}(z_i-z_j)^{\\alpha n_i}$\n\nI tried rewriting the exponential function in the original form:\n\n$\\prod_ke^{\\frac{i\\pi}{2}(k-1)(s_k+1)} = \\prod_ke^{\\frac{i\\pi}{2}(k-1)(2n_k)} =\u00a0\\prod_ke^{i\\pi(k-1)n_k} $\n\n\n"}]}
I need basic explanations
Special Requirements
Upload files (if required)
Drop files here to upload
Add files...
Account info
Already have an account?
Create an account
Name
*
E-mail
*
Password
*
The password must be at least 6 characters.
I agree with
terms & conditions
Create account & Place an order
Please fix the following input errors:
dummy