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{"ops":[{"insert":"Your task in this week is to convert an infix expression to postfix expression. See the code template and sample output given billow for a clear understanding.\nAlso, write a function to evaluate a postfix expression.\nPlease do Comment the steps for understanding. Thanks.\n\nCode template:\n#include <iostream>\n#include <sstream>\nusing namespace std;\n\n\/\/\/ implement your 'stack' here\n\n\nint main()\n{\n\u00a0\u00a0Stack s;\n\u00a0\u00a0string infix, postfix[100];\n\n\u00a0\u00a0cout << \"\\t\\tInfix to Postfix Converter v1.0\\n\";\n\u00a0\u00a0cout << \"\\t\\t===============================\\n\\n\";\n\n\u00a0\u00a0cout << \"Enter an infix expression: \";\n\u00a0\u00a0getline(cin, infix);\n\n\u00a0\u00a0infix += \" )\";\n\u00a0\u00a0s.push(\"(\");\n\n\u00a0\u00a0istringstream token(infix);\n\u00a0\u00a0string t, p;\n\u00a0\u00a0int i=0, j;\n\n\u00a0\u00a0while(token>>t)\n\u00a0\u00a0{\n\u00a0\u00a0\u00a0\u00a0\/\/\/ You have got the input symbol 't'.\n\u00a0\u00a0\u00a0\u00a0\/\/\/ Now you have to process all the input symbols and\n\u00a0\u00a0\u00a0\u00a0\/\/\/ fill in the 'postfix' array accordingly.\n\u00a0\u00a0}\n\n\u00a0\u00a0cout << endl << \"The equivalent postfix expression is: \";\n\u00a0\u00a0for(j=0; j<i; j++) cout << postfix[j] << \" \";\n\u00a0\u00a0cout << endl << endl;\n\n\u00a0\u00a0return 0;\n}\n\n\nSample output:\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Infix to Postfix Converter v1.0\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0===============================\nEnter an infix expression:A + ( B * C - ( D \/ E ^ F ) * G ) * H\nThe equivalent postfix expression is: A B C * D E F ^ \/ G * - H * +\u00a0\nProcess returned 0 (0x0)execution time : 11.891 s\nPress any key to continue.\u00a0\n\n"}]}

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