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90 The solvent dichloromethane (CH2Cl2, molar mass 84.93 g /mol) can be prepared by reaction of methane (CH4, molar mass 16.04 g/mol) with (Cl2 molar mass 17.90 g/mol), according to the balanced equation CH4 + 2CL2 CH2Cl2 + 2HCl. A. If 5.00 g of methane and 15.0 g of cl2 are used, how many moles of each reactant are used? B. What is the limiting reactant? C. How many grams of products are formed? E. If 5.6 g of product are formed, what is the percent yield of the reaction?
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