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Create a shell script which prints the line contents when the line number is divisible by 3 from an input file. Assume the first line is line 1. At the end of the script, if the total number of lines divisible by 3 is greater than 10, print “big”. Otherwise, print “small”. I need help in answering this question. so far this is what I have echo $1 file=$1 awk 'NR%2==0' $file count=$(wc -l $file | grep -o "^[0-9]") if [ $count -gt 20 ] then printf "\nbig\n" else printf "\nsmall\n" fi
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