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In a laboratory experiment, Cu combines with oxygen to produces 2 oxides X and Y. After the experiment, it was determined that 3.07g of X yielded 2.73g copper and 2.90g of Y yielded 2.32g of cooper. Mass of the oxide = ( Mass of copper = ( Mass of oxygen = Number of moles of oxygen = /16 )moles (4 d.p) Number of moles of copper= /63.5 moles Mole ratio of Cu:0 = moles (4 d.p) Simple whole number ratio Cu:0 = Chemical formula of X = Cu To determine the chemical formula of Y Mass of the oxide = ( g(2 d.p) Mass of copper = (2 d.p) Mass of oxygen= Number of moles of oxygen /16 moles (4 d.p) Number of moles of copper /63.5 moles (4 d.p) Mole ratio of Cu:0 = ( )(4 d.p) Simple whole number ratio Cu:0 = Chemical formula of X = Cu The law of chemical combination illustrated by the result above is the Law of
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