Question #64956
How to check if list object has None element?
Expert's answer
# -*- coding: utf-8 -*-
"""
How to check if list object has None element?
"""
v=[1, 2, 3]
print(any(item is None for item in v))
v=[1, None, 3]
print(any(item is None for item in v))
"""
How to check if list object has None element?
"""
v=[1, 2, 3]
print(any(item is None for item in v))
v=[1, None, 3]
print(any(item is None for item in v))
