Answer to Question #303087 in Python for Christine

Question

Create a Python script which will accept a positive integer and will determine the input number if PERFECT, ABUNDANT, DEFICIENT.

PERFECT - if the sum of the divisors of the number except the number itself is equal to the number.

E.g. 6= 1, 2, 3, 6 1+2+3=6

ABUNDANT - if the sum of the divisors of the number except the number itself is greater than the number.

E.g. 12= 1, 2, 3, 4, 6, 12 1+2+3+4+6 = 16

DEFICIENT- if the sum of the divisors of the number except the number itself is less than the number.

E.g. 10= 1, 2, 5, 10 1+2+5=8

Sample Output:

Input a Positive Integer : 20

20 is ABUNDANT!

Answer 1

def type_of_num(num):
    factors = []
    for i in range(1, num + 1):
       if num % i == 0:
           if i != num:
               factors.append(i)
    if sum(factors) == num:
        type_num = "Perfect"
    elif sum(factors) > num:
        type_num = "Abundant"
    else:
        type_num = "Deficient"
    return type_num, factors

print(type_of_num(32))