Answer to Question #243627 in Python for prosper2000

Question

Do Exercise 6.4 from your textbook using recursion and the is_divisible function from Section 6.4. Your program may assume that both arguments to is_power are positive integers. Note that every positive integer that has an exponent of 0 is a power of "1". This includes "0" and "1", itself.

After writing your is_power function, include the following test cases in your script to exercise the function and print the results:

print("is_power(10, 2) returns: ", is_power(10, 2))
print("is_power(27, 3) returns: ", is_power(27, 3))
print("is_power(1, 1) returns: ", is_power(1, 1))
print("is_power(10, 1) returns: ", is_power(10, 1))
print("is_power(3, 3) returns: ", is_power(3, 3))

Answer 1

def is_divisible(x,y):
    if(x%y==0):
        return True;
    else:
        return False;
def is_power(x,y):
    if(x==1):
        return True;
    if(y==1):
        return False;
    if(is_divisible(x,y)==False):
        return False;
    return is_power(x//y,y);
print("is_power(10, 2) returns: ", is_power(10, 2))

print("is_power(27, 3) returns: ", is_power(27, 3))

print("is_power(1, 1) returns: ", is_power(1, 1))

print("is_power(10, 1) returns: ", is_power(10, 1))

print("is_power(3, 3) returns: ", is_power(3, 3))