Question #243089
Diamond
Given an integer value
N, write a program to print a number diamond of 2*N -1 rows as shown below.Input
The first line of input is an integer
N.Explanation
In the given example, the number of rows in the diamond is
5.So, the output should be
....0....
...000...
..00000..
.0000000.
000000000
.0000000.
..00000..
...000...
....0....
Expert's answer
def diamond_shape(number):
x = 0
for row in range(1, number + 1):
for col in range (1, (number - row) + 1):
print(end = " ")
while x != (2 * row - 1):
print("0", end = "")
x = x + 1
x = 0
print()
k = 1
x = 1
for row in range(1, number):
for col in range (1, k + 1):
print(end = " ")
k = k + 1
while x <= (2 * (number - row) - 1):
print("0", end = "")
x = x + 1
x = 1
print()
number=int(input())
diamond_shape(number)
