Answer to Question #238165 in Python for C N Manjula

Question

Given an integer n , write a program to print the closest number that has all the even digits.condifer the lowest number if there is same difference between forward and backward numbers.
Input:17
Output:20
Input :-33
Output:-28

Answer 1

def allDigitsAreEven(number):
    number=abs(number)
    while (number > 0):
        rem = number % 10
        if (rem % 2 != 0):
            return False
        number = int(number / 10)
    return True


number =int(input())
numberCounter1=number
numberCounter2=number


while not allDigitsAreEven(numberCounter1):
    numberCounter1-=1
while not allDigitsAreEven(numberCounter2):
    numberCounter2+=1
    
diff1=number-numberCounter1
diff2=number-numberCounter2


lowestNumber=numberCounter1


if diff1>diff2:
    lowestNumber=numberCounter2
print(lowestNumber)