Answer to Question #291255 in Java | JSP | JSF for kim

Question

Search and Rescue

by CodeChum Admin

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array/list. The next lines contain the integers. The last line contains an integer to be searched.

5

3

21

2

5

23

2

Output

A line containing a string.

Present

Answer 1

import java.util.Scanner;


public class App {


	/**
	 * The start point of the program
	 * 
	 * @param args
	 * 
	 */
	public static void main(String[] args) {
		Scanner keyBoard = new Scanner(System.in);
		int n = keyBoard.nextInt();
		int[] numbers = new int[n];
		for (int i = 0; i < n; i++) {
			numbers[i] = keyBoard.nextInt();
		}
		int target = keyBoard.nextInt();
		int index = -1;
		for (int i = 0; i < n; i++) {
			if (numbers[i] == target) {
				index = i;
			}
		}
		if (index != -1) {
			System.out.println("Present");
		} else {
			System.out.println("None");
		}


		keyBoard.close();
	}
}