2. Search and Rescue
by CodeChum Admin
Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.
Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".
Start coding now!
Input
The first line contains the size of the array/list.
The next lines contain the integers.
The last line contains an integer to be searched.
5
3
21
2
5
23
2
Output
A line containing a string.
Present
import java.util.Scanner;
public class App {
/**
* The start point of the program
*
* @param args
*
*/
public static void main(String[] args) {
Scanner keyBoard = new Scanner(System.in);
int n = keyBoard.nextInt();
int[] numbers = new int[n];
for (int i = 0; i < n; i++) {
numbers[i] = keyBoard.nextInt();
}
int x = keyBoard.nextInt();
boolean isFound = false;
for (int i = 0; i < n; i++) {
if (numbers[i] == x) {
isFound = true;
}
}
if (isFound == true) {
System.out.println("Present");
} else {
System.out.println("None");
}
keyBoard.close();
}
}
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