Answer to Question #272377 in Java | JSP | JSF for harryy

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array/list.

The next lines contain the integers.

The last line contains an integer to be searched.

5

3

21

2

5

23

2

Output

A line containing a string.

Present

Answer 1

Source code

import java.util.Scanner;
public class Main
{
	public static void main(String[] args) {
		Scanner in=new Scanner(System.in);
		int n;
		System.out.print("Enter number of elements in the array: ");
		n=in.nextInt();
		
		int [] arr=new int [n];
		System.out.println("Enter "+n+" integers: ");
		for(int i=0;i<n;i++){
		    arr[i]=in.nextInt();
		}
		
		System.out.print("Enter a random integer to search: ");
		int x=in.nextInt();
		
		boolean b=false;
		for(int i=0;i<n;i++){
		    if(arr[i]==x){
		        b=true;
		    }
		}
		if(b==true){
		    System.out.println("Present");
		}
		else{
		    System.out.println("None");
		}
	}
}

Sample Output 1

Sample Output 2