Question #284147

7. Get all the channels that published at least 5 videos in the year 2018.


Note:


Sort the output in the ascending order of channel_id.


Expected Output Format


channel d


channel_name


no of videos


Expert's answer

SELECT DISTINCT channel_id, channel_name, no_of_videos
FROM  video WHERE year = "2018" 
ORDER BY no_of_videos DESC limit 5;.

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