Answer to Question #285185 in C++ for Francis

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array.

The next lines contain the integers.

The last line contains an integer to be searched.

5
3
21
2
5
23
2

Output

A line containing a string.

Present

Answer 1

#include <iostream>

using namespace std;

int main() {
    int count;
    cin >> count;

    int *numbers = new int[count];
    for (int i = 0; i < count; i++) {
        cin >> numbers[i];
    }

    int num;
    cin >> num;

    bool present = false;
    for (int i = 0; i < count; i++) {
        if (numbers[i] == num) present = true;
    }

    if (present) cout << "Present";
    else cout << "None";

    cout << endl;

    delete[] numbers;

    return 0;
}