Answer to Question #185716 in C++ for Rameen

Question #185716


Q.No.2: A designer in 3D graphics company wants to design a matrix as a two-dimensional array. The size of 2D array could be the last two digit of arid number. Initially he creates a class matrix that provides the member function to check that no array index is out of bounds. Make the member data in the matrix class a 10-by-10 array. A constructor should allow the programmer to specify the actual dimensions of the matrix (provided theyre less than 10 by 10). The member functions that access data in the matrix will now need two index numbers: one for each dimension of the array. Heres what a fragment of a main() program that operates on such a class might look like:

If my Arid Number is 20-Arid-254 then:  // in case of zero consider next digit

 matrix m1(5, 4); // define a matrix object

 int temp = 12345; // define an int value 

m1.putel(7, 4, temp); // insert value of temp into matrix at 7,4 

temp = m1.getel(7, 4); // obtain value from matrix at 7,4


1
Expert's answer
2021-04-26T13:58:36-0400
#include <iostream>

using namespace std;

// declaring class matrix

class matrix
{                               // 10 by 10 matrix is declared in private section
  int abc[10][10];
public:
// constructor to create r by c array
    matrix (int r, int c)
  {
    int abc[r][c];
  }
// member function to get value from array at [r][c]
  int getel (int r, int c)
  {
    return abc[r][c];
  }
// member function to insert value in array at a given position 
  void putel (int r, int c, int temp)
  {
    abc[r][c] = temp;
  }
};

int main ()
{
  matrix m1 (5, 4);             // define a matrix object
  int temp = 12345;             // define an int value
  m1.putel (7, 4, temp);        // insert value of temp into matrix at 7,4
  cout << m1.getel (7, 4);        // obtain value from matrix at 7,4

  return 0;
}

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