Q2.2: Find the first address, last address and the number of addresses of a network whose of the IP addresses is 50.28.22.75/28.
first address: 50.28.22.64/28
last address: 50.28.22.80/28
the number of addresses: 16−2=1416-2=1416−2=14
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments