Answer in Computer Networks for Ali minhal #152256

Question #152256

Perform the subnetting on the below IP Address and find out the number of networks, network of, first host, last host, and broadcast id of each network.
IP Address:120.0.0.0/20

Expert's answer

This is a class B network

$20\ bits\ have\ already\ been\ used\ for\ network,the\ remaining\ i.e\ 32-20=\ 12\ will\ be\ used\ for\ host\ address.$

$The\ total\ number\ of\ hosts\ 2^{12}=4096\ hosts$

$usable \ hosts\ will \ be\ 4096 - 2 = 4094$

Number of networks will be:

$4096 / 256= 16 \ networks$

$First \ IP\ address\ will \ be \ 120.0.0.1$

$Last \ IP\ address \ will\ be\ 120.0.15.254$

$All\ 16\ of\ the\ Possible\ 20\ \ networks\ \ for\ \ 120.0.x.x$

Network Address Usable Host Range Broadcast Address:

120.0.0.0 120.0.0.1 - 120.0.15.254 120.0.15.255

120.0.16.0 120.0.16.1 - 120.0.31.254 120.0.31.25

120.0.32.0 120.0.32.1 - 120.0.47.254 120.0.47.255

120.0.48.0 120.0.48.1 - 120.0.63.254 120.0.63.255

120.0.64.0 120.0.64.1 - 120.0.79.254 120.0.79.255

120.0.80.0 120.0.80.1 - 120.0.95.254 120.0.95.255

120.0.96.0 120.0.96.1 - 120.0.111.254 120.0.111.255

120.0.112.0 120.0.112.1 - 120.0.127.254 120.0.127.255

120.0.128.0 120.0.128.1 - 120.0.143.254 120.0.143.255

120.0.144.0 120.0.144.1 - 120.0.159.254 120.0.159.255

120.0.160.0 120.0.160.1 - 120.0.175.254 120.0.175.25

120.0.176.0 120.0.176.1 - 120.0.191.254 120.0.191.255

120.0.192.0 120.0.192.1 - 120.0.207.254 120.0.207.255

120.0.208.0 120.0.208.1 - 120.0.223.254 120.0.223.255

120.0.224.0 120.0.224.1 - 120.0.239.254 120.0.239.255

120.0.240.0 120.0.240.1 - 120.0.255.254 120.0.255.255

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