Question

#include<stdio.h>
main()
{
int x=4,y=0,z;
while(x>=0)
{
x--;
y++;
if(x==y)
continue;
else
printf("\n %d %d",x,y);
}

What is the output of this program? Please explain the logic for the output.

Answer 1

Answer on Question #54847 – Programming – C

Condition

What is the output of this program? Please explain the logic for the output.

int main()
{
    int x = 4, y = 0;
    while (x >= 0)
    {
        x--;
        y++;
        if (x == y)
            continue;
        else
            printf("\n %d %d", x, y);
    }
    return 0;
}

Solution

You declare variable x with value 4 and variable y with value 0. Later you have loop, which will work until x is more than 0 and x is equal 0. In every loop iteration variable x is decrementing (it means x − 1) and variable y is incrementing (it means y + 1). Later you have condition – if variable x is equal variable y in this loop iteration, program will go to the next loop iteration immediately. If variable x on this loop iteration doesn't equal variable y, program will print variables x and y. In the second loop iteration variable x is equal 2 and variable y is equal 2, but you will not see this in output, because in this moment your program will work with "if" operator.

Answer

Output:

3 1

1 3

0 4

-1 5

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