Question

Explain more about Young's modulus

Answer 1

Answer on Question #64757, Physics / Solid State Physics

Explain more about Young's modulus.

Answer:

$$E = \frac {\sigma}{\varepsilon} = \frac {F l _ {0}}{S \Delta l}$$

Where $E$ is a constant that characterizes the elastic properties of the material depends on its physical state called Young's modulus.

The physical meaning of the Young's modulus:

If $\Delta l = l_{0}$, then $\varepsilon = 1$ and the tension $\sigma = E$. Therefore, the Young's modulus can be defined as the tensile stress that would lead to a doubling of the length of the rod, subject to Hooke's law. However, none of the actual material other than rubber and some polymers, as not capable of withstanding large deformations.

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