Question #51438

How much mass does an electron gain when it is accelerated to a kinetic energy of
500 keV?
1

Expert's answer

2015-04-10T02:46:56-0400

Answer on Question #51438, Physics, Solid State Physics

How much mass does an electron gain when it is accelerated to a kinetic energy of 500 keV?

Solution:

Mass-energy equivalence for electron m0c2=511keVm_0c^2 = 511\,keV.

The kinetic energy of electron is given by Eq.(1)


EK=mc2m0c2E_K = mc^2 - m_0c^2


where m=m0/1v2/c2m = m_0 / \sqrt{1 - v^2 / c^2}, m0=9.11031kgm_0 = 9.1 \cdot 10^{-31}\,kg is the electron mass of tranquility; cc is the velocity of light; vv is the velocity of the electron.

From Eq.(1)


m=EK+m0c2c2=8.1761014+81014(3108)2=1.81030kgm = \frac{E_K + m_0c^2}{c^2} = \frac{8.176 \cdot 10^{-14} + 8 \cdot 10^{-14}}{\left(3 \cdot 10^8\right)^2} = 1.8 \cdot 10^{-30}\,kg


where m0c2=511keV=8.1761014Jm_0c^2 = 511\,keV = 8.176 \cdot 10^{-14}\,J; EK=500keV=8.0001014JE_K = 500\,keV = 8.000 \cdot 10^{-14}\,J

Answer: m=EK+m0c2c2=8.1761014+81014(3108)2=1.81030kgm = \frac{E_K + m_0c^2}{c^2} = \frac{8.176 \cdot 10^{-14} + 8 \cdot 10^{-14}}{\left(3 \cdot 10^8\right)^2} = 1.8 \cdot 10^{-30}\,kg

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