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Question #339665
Find the electric flux in a sphere of radius 0.48 cm from a charge of 55 nC.
Expert's answer
ϕ
=
∮
E
d
A
=
q
ϵ
0
\phi=\oint EdA =\frac{q}{\epsilon_0}
ϕ
=
∮
E
d
A
=
ϵ
0
q
ϕ
=
55
∗
1
0
−
9
8.85
∗
1
0
−
12
=
6215
N
⋅
m
2
/
C
\phi=\frac{55*10^{-9}}{8.85*10^{-12}}=6215\:\rm N \cdot m^2/C
ϕ
=
8.85
∗
1
0
−
12
55
∗
1
0
−
9
=
6215
N
⋅
m
2
/C
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#340153
on Dec 2023
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