Since energy is at the level n En=h2n28ml2E_n = \frac {h^{2}n^{2}}{8ml^{2}}En=8ml2h2n2
then the energy difference ΔEn=En+1−En=h2(2n+1)8ml2\Delta E_n = E_{n+1} - E_n = \frac{h^{2}(2n+1)}{8ml^{2}}ΔEn=En+1−En=8ml2h2(2n+1)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment