Question #91430

Calculate the energy of neutrons that is seen for a Bragg angle of 45 degree for a first order reflection if the brass space 1.22A

Expert's answer

By Bragg-Wulf condition

λ=22d\lambda = \sqrt[2]2d

respectively

ϵ=h24d2m=29.510286.68=4.41021(J)\epsilon = \frac{h^{2}}{4d^{2}m}= \frac{29.5\cdot10^{-28}}{6.68} = 4.4\cdot10^{-21} (J)


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