Question

The orbital angular momentum of a single 2s electron is (h is the
Planck’s constant) :
(A) h/2
(B) h/4
(C) h√ 2 / 2
(D) Zero

Answer 1

Orbital angular momentum:

$$L=\frac{\sqrt{l(l+1)}h}{2 \pi}$$

For s-orbital:

$$l=0$$

Thus,

$$L=0$$

Answer: (D) Zero.