Question #87508
Consider a particle in a Coulomb potential in three dimensional space. In Heisenberg's picture,d/dt⟨L^z⟩=0, where L^z is the z-component of angular momentum operator. Using this information which of the following choice(s) are correct:
1.H,L^z,L^x share simulatenous eigenbasis

2.L^z,L^x share simultaneous eigenbasis

3.H,L^z share simultaneous eigenbasis

4.L^.L^,L^z,L^x share simultaneous eigenbasis
1
Expert's answer
2019-04-08T12:56:42-0400

Simultaneous eigenbasis can be shared only by pairwise commuting collections of operators. Since, in Heisenberg's picture, we have

ddtLz=i[H,Lz]=0,\frac{d}{dt} L_z = \frac{i}{\hbar} \left[ H , L_z \right] = 0 \, ,

we observe that HH and LzL_z commute and, therefore, share simultaneous eigenbasis. On the other hand, LzL_z and LxL_x do not commute, [Lz,Lx]=iLy\left[ L_z , L_x \right] = i L_y, so they cannot share simultaneous eigenbasis. Thus, there is only one correct answer to this question.


Answer: H,LzH , L_z share simultaneous eigenbasis.


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