Answer on Question #85009 Physics / Quantum Mechanics
For the operator A ^ = a x ^ + i b p ^ \hat{A} = a\hat{x} + ib\hat{p} A ^ = a x ^ + ib p ^ where a a a and b b b are constants, calculate [ A ^ , x ^ ] [\hat{A}, \hat{x}] [ A ^ , x ^ ] and [ A ^ , A ^ ] [\hat{A}, \hat{A}] [ A ^ , A ^ ] .
Solution:
The commutation relation between position and momentum operators is as follows
[ p ^ , x ^ ] = − i ℏ [ \hat {p}, \hat {x} ] = - i \hbar [ p ^ , x ^ ] = − i ℏ
So
[ A ^ , x ^ ] = [ a x ^ + i b p ^ , x ^ ] = a [ x ^ , x ^ ] ⏟ 0 + i b [ p ^ , x ^ ] ⏟ − i ℏ = b ℏ \left[ \hat {A}, \hat {x} \right] = \left[ a \hat {x} + i b \hat {p}, \hat {x} \right] = a \underbrace {\left[ \hat {x} , \hat {x} \right]} _ {0} + i b \underbrace {\left[ \hat {p} , \hat {x} \right]} _ {- i \hbar} = b \hbar [ A ^ , x ^ ] = [ a x ^ + ib p ^ , x ^ ] = a 0 [ x ^ , x ^ ] + ib − i ℏ [ p ^ , x ^ ] = b ℏ
For any operator A ^ \hat{A} A ^
[ A ^ , A ^ ] = 0 \left[ \hat {A}, \hat {A} \right] = 0 [ A ^ , A ^ ] = 0
Answer: [ A ^ , x ^ ] = b ℏ \left[\hat{A},\hat{x}\right] = b\hbar [ A ^ , x ^ ] = b ℏ , [ A ^ , A ^ ] = 0 \left[\hat{A},\hat{A}\right] = 0 [ A ^ , A ^ ] = 0
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