Question #85009

For the operator A = a x + i b p where a and b are constants, calculate [A, x] and
[A, A].

Expert's answer

Answer on Question #85009 Physics / Quantum Mechanics

For the operator A^=ax^+ibp^\hat{A} = a\hat{x} + ib\hat{p} where aa and bb are constants, calculate [A^,x^][\hat{A}, \hat{x}] and [A^,A^][\hat{A}, \hat{A}] .

Solution:

The commutation relation between position and momentum operators is as follows


[p^,x^]=i[ \hat {p}, \hat {x} ] = - i \hbar


So


[A^,x^]=[ax^+ibp^,x^]=a[x^,x^]0+ib[p^,x^]i=b\left[ \hat {A}, \hat {x} \right] = \left[ a \hat {x} + i b \hat {p}, \hat {x} \right] = a \underbrace {\left[ \hat {x} , \hat {x} \right]} _ {0} + i b \underbrace {\left[ \hat {p} , \hat {x} \right]} _ {- i \hbar} = b \hbar


For any operator A^\hat{A}

[A^,A^]=0\left[ \hat {A}, \hat {A} \right] = 0


Answer: [A^,x^]=b\left[\hat{A},\hat{x}\right] = b\hbar , [A^,A^]=0\left[\hat{A},\hat{A}\right] = 0

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