Question #84388

Let A and B be vector operators. This means that they have certain
nontrivial commutation relations with the angular momentum opera￾tors. Use those relations to prove that A·B commutes with Jx, Jy, and
Jz.

Expert's answer

We have nontrivial commutation relations. Then consider the following provisions. We have the scalar product of vectors A and B, that is, it will be the following expression: A·B=xAxB+yAyB+zAzB.

Let's look at the switch: [A·B, Jx]=xAxBJx-JxxAxB=0, because the product of X will be a number, and it can be rearranged in any order.

Let's look at the switch: [A·B, Jy]=yAyBJy-JyyAyB=0, because the product of Y will be a number, and it can be rearranged in any order.

Let's look at the switch: [A·B, Jz]=zAzBJz-JzzAzB=0, because the product of X will be a number, and it can be rearranged in any order.

In this way, A·B and Jx, A·B and Jy, A·B and Jz commute.

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