Question #72764

For what values of the constant (c) will the function f(x)=Ae-αx be an eigen function of the operator Q=d/dx d/dx+2/x d/dx+c/x? Whats the corresponding eigen value?

Expert's answer

Answer on Question #72764, Physics / Quantum Mechanics

Question

For what values of the constant (c) will the function f(x)=Aeαxf(x) = Ae^{-\alpha x} be an eigen function of the operator Q=d/dx d/dx+2/x d/dx+c/xQ = d/dx \ d/dx + 2/x \ d/dx + c/x? What's the corresponding eigen value?

Solution

Action of the operator QQ on function f(x)f(x) is


Qf(x)=Aeαx(α2+c2αx)Qf(x) = Ae^{-\alpha x} \left( \alpha^2 + \frac{c - 2\alpha}{x} \right)


In case of c=2αc = 2\alpha function f(x)f(x) is the solution of eigenequation


Qf(x)=λf(x),Qf(x) = \lambda f(x),


with λ=α2\lambda = \alpha^2 being the eigenvalue.

Answer: c=2αc = 2\alpha and λ=α2\lambda = \alpha^2.

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