Question #68641

if A^ and B^ are hermitian and anti-hermitian operators respectively.check the hermiticity of the commutator [A^,B^] of the two operators .

Expert's answer

Answer on Question #68641, Physics / Quantum Mechanics |

Question

if A^ and B^ are hermitian and anti-hermitian operators respectively, check the hermiticity of the commutator [A^,B^] of the two operators.

Solution

We have

A^+=A^\hat{A}^{+} = \hat{A} — hermitian operator,

B^+=B^\hat{B}^{+} = -\hat{B} — anti-hermitian operator.

We remind the definition of the commutator

[A^,B^]=A^B^B^A^[\hat{A},\hat{B}] = \hat{A}\hat{B} -\hat{B}\hat{A}

and the property of hermitian conjugation

(A^B^)+=B^+A^+(\hat{A}\hat{B})^{+} = \hat{B}^{+}\hat{A}^{+}.

Now we can check the hermiticity of the commutator

[A^,B^]+=(A^B^B^A^)+=(A^B^)+(B^A^)+=B^+A^+A^+B^+=B^A^+A^B^=[A^,B^][\hat{A},\hat{B}]^{+} = (\hat{A}\hat{B} -\hat{B}\hat{A})^{+} = (\hat{A}\hat{B})^{+} - (\hat{B}\hat{A})^{+} = \hat{B}^{+}\hat{A}^{+} - \hat{A}^{+}\hat{B}^{+} = -\hat{B}\hat{A} +\hat{A}\hat{B} = [\hat{A},\hat{B}]

Thus, commutator [A^,B^][\hat{A},\hat{B}] is hermitian.

Answer: commutator [A^,B^][\hat{A},\hat{B}] is hermitian.

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