Question #67991

Consider the 1s state of hydrogen, calculate the probability of finding the electron in the region given below: 0<=r <= 0.5a0

Expert's answer

Answer on Question #67991 - Physics – Quantum Mechanic

Question:

Consider the 1s state of hydrogen, calculate the probability of finding the electron in the region given below: 0r0.5a00 \leq r \leq 0.5a0

Solution:

A problem in integration of


4a030a0/2e2ra0r2dr\frac{4}{a_0^3} \int_0^{a_0/2} e^{-\frac{2r}{a_0} r^2} dr0a0/2e2ra0r2dr=a02e2ra0[r2+a0r+a02]\int_0^{a_0/2} e^{-\frac{2r}{a_0} r^2} dr = -\frac{a_0}{2} e^{-\frac{2r}{a_0}} \left[ r^2 + a_0 r + \frac{a_0}{2} \right]


Thus 4a030a0/2e2ra0r2dr=2a02e2ra0[r2+a0r+a02]a0/2\frac{4}{a_0^3} \int_0^{a_0/2} e^{-\frac{2r}{a_0} r^2} dr = -\frac{2}{a_0^2} e^{-\frac{2r}{a_0}} \left[ r^2 + a_0 r + \frac{a_0}{2} \right]^{a_0/2}

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