Question

Q. Find frequency, energy and momentum of a photon having wavelength of 46 pm.

Answer 1

Answer on Question #58594, Physics / Quantum Mechanics |

Find frequency, energy and momentum of a photon having wavelength of 46 pm.

Solution:

The frequency is

$$f = \frac{c}{\lambda} = \frac{3 \cdot 10^{8} \ \mathrm{m/s}}{46 \cdot 10^{-12} \ \mathrm{m}} = 6.52 \cdot 10^{18} \ \mathrm{Hz}$$

The energy is

$$E = \frac{hc}{\lambda} = hf = 6.625 \cdot 10^{-34} \cdot 6.52 \cdot 10^{18} = 4.32 \cdot 10^{-15} \ \mathrm{J}$$ $$E = \frac{4.32 \cdot 10^{-15}}{1.6 \cdot 10^{-19}} = 27 \cdot 10^{3} \ \mathrm{eV} = 27 \ \mathrm{keV}$$

The momentum is

$$p = \frac{h}{\lambda} = \frac{6.625 \cdot 10^{-34} \ \mathrm{J} \cdot \mathrm{s}}{46 \cdot 10^{-12} \ \mathrm{m}} = 1.44 \cdot 10^{-23} \ \mathrm{kg} \cdot \mathrm{m/s}$$

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