Question #58591

Q. Find work function for a silver surface for which the threshold frequency of incident light is 1.1х1015 Hz.

Expert's answer

Answer on Question #58591, Physics / Quantum Mechanics

Find work function for a silver surface for which the threshold frequency of incident light is 1.1×1015Hz1.1 \times 10^{15} \, \text{Hz}.

Find: A – ?

Given:

umin=1,1×1015Hzu_{\min} = 1,1 \times 10^{15} \, \text{Hz}

h=6,626×1034J×sh = 6,626 \times 10^{-34} \, \text{J} \times \text{s}

Solution:

Equation of external photoelectric effect:


hu=A+mvmax22(1),h u = A + \frac{m v_{\max}^2}{2} (1),


where huh u – energy of photon,

A – electron work function of the metal surface,

mvmax22\frac{m v_{\max}^2}{2} – the maximum kinetic energy of the electron

Of (1) humin=A(2)\Rightarrow h u_{\min} = A \, (2)

Of (2) A=7,29×1019J\Rightarrow A = 7,29 \times 10^{-19} \, \text{J}

1eV1,6×1019J1 \, \text{eV} - 1,6 \times 10^{-19} \, \text{J}

A 7,29×1019J-7,29 \times 10^{-19} \, \text{J}

A=4,56eVA = 4,56 \, \text{eV}

Answer:

4,56eV4,56 \, \text{eV}

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