Question #53073

The mass of a nucleus is 0.042 amu less than the sum of the masses of 3 protons and 4 neutrons. What is the binding energy per nucleon in 7 3Li ?

Expert's answer

Answer on question #53073, Physics / Quantum Mechanics

Question The mass of a nucleus is 0.042 amu less than the sum of the masses of 3 protons and 4 neutrons. What is the binding energy per nucleon in 7 3Li ?

Solution Binding energy per nucleon is

E=Δmc2/per nucleon=0.042c23+4=0.06 amu=0.06931.5=55.89 MeVE=\Delta mc^{2}/per\ nucleon=\frac{0.042c^{2}}{3+4}=0.06\ amu=0.06\cdot 931.5=55.89\ MeV

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